A lottery ticket contains five unique numbers. A set of unique numbers does not contain repeated elements. The winning combination of this lottery is chosen by picking five unique numbers. Define a function matches(ticket, winners) that takes two lists and returns an integer that says how many numbers the two lists have in common.

Answer explained below

Explanation:

I have given two approaches in implementing the solution.

1. Using the for loop, in which you have to iterate over all the elements in list 1 and check in list 2

2. Use the set intersection method. As intersection will give u the common elements. And we can get there length by using len method.

I have added the code along with the snapshot and inline comment for the ease of you to understand. Please check the methods below. You can use either of them.

METHOD-1:

CODE

def matches(tickets,winner):

tickets = set(tickets)

winner = set(winner)

counter = 0 #To Count the common elements

for i in tickets: # Iterate over all the elements in tickets.

if i in winner: # Check the element in the winner list

counter = counter+1

return counter

METHOD -2:

CODE

def matches(tickets, winner):

tickets = set(tickets)

winner = set(winner)

return len(tickets.intersection(winner))

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