Hich virtual printing feature is usually done as an export rather than a true print?
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Computers and Technology, 18.02.2020 20:33 clarkster112679
Hich virtual printing feature is usually done as an export rather than a true print?
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Computers and Technology, 22.06.2019 14:00
What are procedures that keep a data base current
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Computers and Technology, 22.06.2019 20:10
Assume the existence of a bankaccount class. define a derived class, savingsaccount that contains two instance variables: the first a double, named interestrate, and the second an integer named interesttype. the value of the interesttype variable can be 1 for simple interest and 2 for compound interest. there is also a constructor that accepts two parameters: a double that is used to initialize the interestrate variable, and a string that you may assume will contain either "simple", or "compound", and which should be used to initialize the interesttype variable appropriately. there should also be a pair of functions getinterestrate and getinteresttype that return the values of the corresponding data members (as double and int respectively).
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Computers and Technology, 22.06.2019 21:30
The salespeople at hyperactive media sales all use laptop computers so they can take data with them on the road. you are a salesperson for superduper lightspeed computers talking to hyperactive media sales about upgrading the laptops to windows 10. explain how network location awareness in windows 10 would make the laptops more secure.
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Computers and Technology, 23.06.2019 00:40
Consider the following statements: struct nametype{string first; string last; }; struct coursetype{string name; int callnum; int credits; char grade; }; struct studenttype{nametype name; double gpa; coursetype course; }; studenttype student; studenttype classlist[100]; coursetype course; nametype name; mark the following statements as valid or invalid. if a statement is invalid, explain why.a.) student.course.callnum = "csc230"; b.) cin > > student.name; c.) classlist[0] = name; d.) classlist[1].gpa = 3.45; e.) name = classlist[15].name; f.) student.name = name; g.) cout < < classlist[10] < < endl; h.) for (int j = 0; j < 100; j++)classlist[j].name = name; i.) classlist.course.credits = 3; j.) course = studenttype.course;
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