Assuming that the user enters 45 and 62 as inputs for n1 and n2, respectively, what is the output of the following code snippet?

System. out. print ("Enter a number: ");
Scanner in = new Scanner (System. in);
String n1 = in. next ();
System. out. print ("Enter another number: ");
String n2 = in. next ();
String result = n1 + n2;
System. out. print (result);

4562

45 + 62

62

107

Which of the following conditions is true only when the integer variables a, b, and c contain three different values?

a != b != c

(a != b) || (a != c) || (b != c)

(a != b) && (a != c) && (b != c)

!((a == b) && (b == c) && (a == c))

a) 4562

b) (a != b) || (a != c) || (b != c)

(a != b) && (a != c) && (b != c)

!((a == b) && (b == c) && (a == c))

Explanation:

a) The user input of 45 and 62 are received as a String (n1 and n2). Then result concatenate the value of 45 and 62 which is 4562. Result variable uses the concatenate operator '+'.

b)

(a != b) && (a != c) && (b != c) is correct as each of the individual condition must be true before it evaluate to true. Meaning a is not equals to b and a is not equals to c and b is not equals to c.

(a != b) || (a != c) || (b != c) is correct because it evaluate to true if at least one of the condition is satisfied.

!((a == b) && (b == c) && (a == c)) is correct because each individual condition is false and the logical combination of false and false and false equals false, then the negation of false is true

i think its d if im not mistaken

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