Input A B C * + D E / F * - Output (A+(B*C))-((D/E)*F)) Algorithm of Postfix to infix 1. Push postfix notation to the PostfixStack reverse order ( eg. push - * F / E D + * C B A) 2. while there are no data at PostfixStack 3. read one symbol from the PostfixStack 4. if the symbol is an operand 5. push it into the InfixStack 6. else 7. pop the top 2 values from the InfixStack 8. put the operator between two operand 9. Encapsulate the resulted string with parenthesis 10. if there is only one value in the stack That value in the stack is the desired Infix notation.

What is the foundation for proper monitoring, load balancing and routing in distributed systems

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Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }