Create an application containing an array that stores 10 integers. The application should call five methods that in turn (1) display all the integers, (2) display all the integers in reverse order, (3) display the sum of the integers, (4) display all values less than a limiting argument, and (5) display all values that are higher than the calculated average value. Then, create another array that store 5 integers. Pass the two arrays to a method that will display the integer value(s), if any, that appear in both arrays (note that the two arrays can have no stored values in common). Save the file as ArrayMethodDemo. java.

    public class Main {    public static void main(String[] args) {        int myArray[] = {3, 7, 2, 5, 9,11, 24, 6, 10, 12};        int myArray2 [] = {1, 2, 3, 4 ,5};        displayValue(myArray);        reverseDisplay(myArray);        displaySum(myArray);        displayLess(myArray, 10);        displayHighAvg(myArray);        displayBoth(myArray, myArray2);    }    public static void displayValue(int arr[]){        for(int i = 0; i < arr.length; i++){            System.out.print(arr[i] + " ");        }        System.out.println();    }    public static void reverseDisplay(int arr[]){        for(int i = arr.length-1; i >= 0; i--){            System.out.print(arr[i] + " ");        }        System.out.println();    }    public static void displaySum(int arr[]){        int sum = 0;        for(int i = 0; i < arr.length; i++){            sum += arr[i];        }        System.out.println(sum);    }    public static void displayLess(int arr[], int limit){        for(int i = 0; i < arr.length; i++){            if(arr[i] < limit){                System.out.print(arr[i] + " ");            }        }        System.out.println();    }    public static void displayHighAvg(int arr[]){        int sum = 0;        for(int i = 0; i < arr.length; i++){            sum += arr[i];        }        double avg = sum / arr.length;        for(int i = 0; i < arr.length; i++){            if(arr[i] > avg){                System.out.print(arr[i] + " ");            }        }        System.out.println();    }    public static void displayBoth(int arr1[], int arr2 []){        for(int i = 0; i < arr2.length; i++){            for(int j = 0; j < arr1.length; j++){                if(arr1[j] == arr2[i]){                    System.out.print(arr1[j] + " ");                }            }        }        System.out.println();    } }

Explanation:

There are five methods written to solve all the problems stated in the question.

Method 1 : displayValue    (Line 15 - 21)

This is the method that take one input array and use the print() method to display the all the elements in the array.

Method 2: reverseDisplay (Line 23 - 26)

This method will take one input array and print the value in the reverse order. We just need to start with the last index when running the for-loop to print the value.

Method 3: displaySum (Line 31 - 37)

This method will take one input array and use a for-loop to calculate the total of the values in the array.

Method 4: displayLess (Line 39 - 47)

This method will take one two inputs, a array and a limit. We use the limit as the condition to check if any value less than the limit, then the value will only be printed.

Method 5: displayHighAvg (Line 50 - 64)

This method will take one input array and calculate the average. The average will be used to check if any element in the array higher than it, then the value will only be printed.

Method 6: displayBoth  (Line 66 - 75)

This method will take two input arrays and compare both of them to find out if any value appears in both input arrays and print it out.

Ligma is the answer