LAB: Even/odd values in an array

Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with an integer indicating the number of integers that follow. Assume that the list will always contain less than 20 integers.

Ex: If the input is: 5 2 4 6 8 10

the output is: all even

Ex: If the input is: 5 1 3 5 7 9

the output is: all odd

Ex: If the input is: 5 1 2 3 4 5

the output is:

not even or odd
Your program must define and call the following two functions. IsArrayEven returns true if all integers in the array are even and false otherwise. IsArrayOdd returns true if all integers in the array are odd and false otherwise.
bool IsArrayEven(int inputVals[], int numVals)
bool IsArrayOdd(int inputVals[], int numVals)

PLease answer in c

Explanation:

Firstly, write two functions to check if the input array is all even or all odd (Line 3-22). The key idea is to use modulus operator to check if a number % 2 equal to 0, it is an even number, if not, it is an odd. So long as one of the number is odd in the isArrayEven function, the function shall return false (Line 7). If no odd value detected, it return true (Line 11). The similar code logic is applied to isArrayOdd function too.  

Then, we can call the two functions sequentially in the main program. If isArrayEven function return true, it display all even message (Line 28-29). If odd, display all odd (Line 30 -31). If neither, display not even or odd (Line 32-33).

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the answer to your question is ⇔ d. the nether

explanation: