Computers and Technology, 10.03.2020 00:40 ciel8809
Write a C++ expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal".
#include
#include
using namespace std;
int main() {
double targetValue = 0.3333;
double sensorReading = 0.0;
sensorReading = 1.0/3.0;
if (/* Your solution goes here */) {
cout << "Equal" << endl;
}
else {
cout << "Not equal" << endl;
}
return 0;
}
Answers: 1
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Write a C++ expression that will cause the following code to print "Equal" if the value of sensorRea...
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