Given 4 integers, output their product and their average, using integer arithmetic.

Ex: If the input is:

8 10 5 4
Given:

import java. util. Scanner;

public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System. in);
int num1;
int num2;
int num3;
/* Type your code here. */
}
}

the output is:

1600 6
Note: Integer division discards the fraction. Hence the average of 8 10 5 4 is output as 6, not 6.75.

Note: The test cases include four very large input values whose product results in overflow. You do not need to do anything special, but just observe that the output does not represent the correct product (in fact, four positive numbers yield a negative output; wow).

Submit the above for grading. Your program will fail the last test cases (which is expected), until you complete part 2 below.

Part 2

Also output the product and average, using floating-point arithmetic.

Output each floating-point value with three digits after the decimal point, which can be achieved as follows:
System. out. printf("%.3f", yourValue);

Ex: If the input is 8 10 5 4, the output is:

1600 6
1600.000 6.750
Note that fractions aren't discarded, and that overflow does not occur for the test case with large values.

LAB

import java.util.Scanner;

public class num10 {

   public static void main(String[] args) {

   Scanner scnr = new Scanner(System.in);

   int num1 = scnr.nextInt();

   int num2 = scnr.nextInt();

   int num3 = scnr.nextInt();

   int num4 = scnr.nextInt();

   int product = num1*num2*num3*num4;

   int average = (num1+num2+num3+num4)/4;

   System.out.println(product+" "+average);

   // Part Two

   double prod = num1*num2*num3*num4;

   double ave =  (double)(num1+num2+num3+num4)/4;

   System.out.printf("%.3f", prod);

   System.out.println();

   System.out.printf("%.3f", ave);

   }

}

Explanation:

As required in the question, four variables are created to hold values for num1, num2,num3,num4.

The product  is evaluated:  int product = num1*num2*num3*num4;

The average is evaluated: int average = (num1+num2+num3+num4)/4;

These are output to the screen

In part two;

The product and average are declared as type double so as to hold floating point number

double ave =  (double)(num1+num2+num3+num4)/4; In order to avoid integer division which discards the remainder, a type casting is performed on the 4 input variables.

Finally using printf method new values of product and average is outputed.

i want to say d but i could be wrong however it is organized if that could happen..

hope it could