Computers and Technology, 16.03.2020 20:43 kingteron6166

SELECT vendor_name, COUNT(*) AS number_of_invoices, MAX(invoice_total - payment_total - credit_total) AS balance_due FROM vendors v JOIN invoices i ON v. vendor_id = i. vendor_id WHERE invoice_total - payment_total - credit_total > (SELECT AVG(invoice_total - payment_total - credit_total) FROM invoices) GROUP BY vendor_name ORDER BY balance_due DESC (Please refer to the code example above.) When this query is executed, the rows will be sorted by:.a. balance_due in descending sequence b. invoice_id c. vendor_id

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SELECT vendor_name, COUNT(*) AS number_of_invoices, MAX(invoice_total - payment_total - credit_total...

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