Consider the following source code, where k, l and m are constants declared with #define. The struct lnode is as defined from problem 1, repeated here:

struct lnode {
struct lnode *next; // points to next node address

char *str; // points to 16-character string

};

You will need to determine the values for k, l and m, which are the dimensions of a 3-D array named A.
struct lnode A[k][l][m];
int store_ele(int h, int i, int j, struct lnode dest) {

A[h][i][j] = dest;
return sizeof(A);

}

On compiling this program (with gcc -O2 -S -fno-asynchronous-unwind-tables), gcc generates the following assembly code for the store_ele function:

store_ele:
movslq %esi, %rsi
movslq %edi, %rdi
movslq %edx, %rax
imulq $343 %rdi, %rdi
leaq (%rsi,%rsi,2), %rdx
salq $4, %rdx
addq %rsi, %rdx
addq %rdi, %rdx
addq %rax, %rdx
leaq A(%rip), %rax
salq $4, %rdx
addq %rax, %rdx
movl $268912, %eax
movq %rcx, (%rdx)
movq %r8, 8(%rdx)
ret
Use your reverse engineering skills to determine the values of k, l and m, based on the assembly code. Show your work and the steps required to determine k, l and m on the next page as answer 2.2. You may attach additional pages as needed. Place the discovered values for k, l and m in 2.1

I know that the maximum size of the array is 268912 and since its a struct its gonna be 16.

K*l*M*16 = 268912 and if dive 268 912 will get 16807. But I really dont know how to find K, L and M.

There's no other information that I can be added..This is the full question will all of the information.