Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive. After the loop terminates, it prints out, on a line by itself and separated by spaces, the sum of all the even integers read, the sum of all the odd integers read, a count of the number of even integers read, and a count of the number of odd integers read, all separated by at least one space. Declare any variables that are needed. ASSUME the availability of a variable, stdin, that references a Scanner object associated with standard input.

import java.util.Scanner;

public class num15 {

   public static void main(String[] args) {

   Scanner in = new Scanner(System.in);

       int sumEven =0;

       int sumOdds =0;

       int countEven =0;

       int countOdd =0;

       System.out.println("Enter numbers");

       int num = in.nextInt();

       if(num%2==0){

           sumEven = num;

           countEven++;

       }

       else{

           sumOdds =num;

           countOdd++;

       }

    while(num>0){

        System.out.println("Enter another number: ");

        num = in.nextInt();

        if(num%2==0){

            sumEven= sumEven+num;

            countEven++;

        }

        else{

            sumOdds = sumOdds+num;

            countOdd++;

        }

   }

       System.out.println("Sum of Odds "+sumOdds);

       System.out.println("Sum of Evens "+sumEven);

       System.out.println("Count Odds "+countOdd);

       System.out.println("Count Evens "+(countEven-1));

   }

}

Explanation:

The complete program in Java is given above

Using the scanner class the user is repetitively prompted to enter a number

The while(num>0) loop ensures that only positive numbers greater than 0 are entered, when 0 or a negative number is entered the loop terminates.

Within the while loop an if/else statement is used to keep track of the sumEvens, countEvens, sumOdds and countOdds

The values of these variables are printed on separate line

See code output attached.