Write an expression that continues to bid until the user enters 'n'. Sample output with inputs: 'y' 'y' 'n' I'll bid $7! Continue bidding? I'll bid $15! Continue bidding? I'll bid $23! Continue bidding?

#include <iostream>

#include <cstdlib>  

using namespace std;

int main() {

  char Keep_Going = '-';

  int nextBid = 0;

  srand(5);

  while (Keep_Going != 'n') { //<-- solution

     nextBid = nextBid + (rand()%10 + 1);

     cout << "I'll bid $" << nextBid << "!" << endl;

     cout << "Continue bidding? ";

     cin >> Keep_Going;

  }

  cout << endl;

  return 0;

}

Written in Python:

import random

random.seed(5)

keep_going = '-'

next_bid = 0

while keep_going != 'n':

  next_bid = next_bid + random.randint(1, 10)

  print('I\'ll bid ${}!'.format(next_bid))

  print('Continue bidding?', end=' ')

  keep_going = input()

Explanation:

click the big logo on the top left of the screen.   hope this !

-ttl

answer; defense;