Assume that you are given both the preorder and postorder traversal of some binary tree t. Prove that this information, taken together, is not necessarily sufficient to reconstruct t uniquely, even if each value in t occurs only once.

answer: internal fragmentation is the difference between the (fixed) size of a memory hole and the data within in that memory. for example, if a 1,024 byte block of memory holds 800 bytes of data, then the 224 bytes difference is considered lost to internal fragmentation.

external fragmentation occurs when the sum of memory fragments is large enough to satisfy a request, but the holes are non-contiguous and the request cannot be satisfied. this can occur when memory is dynamically allocated and freed.

explanation:

the printer can be used in a both wired and wireless network, only one of the connection methods can be used at one time when the wireless setting is enabled, the wired (ethernet) setting is disabled.

but first you need to

`connect the cord to your computer

`open settings app from the start menu

`click devices

`than click add printer or scanner

and than you should be able to do it from there, if not let me know i can you! : )