Reset to Starter Code

Write 3 functions in the starter code below such that:

add_to_dict(): takes a dictionary, a key, a value and adds the key, value pair to the dictionary. If key is already in dictionary then it displays the error message: "Error. Key already exists.". Returns dictionary.

remove_from_dict(): takes a dictionary and key and removes the key from the dictionary. Returns dictionary. If no such key is found in the dictionary then it prints: "No such key exists in the dictionary.". Hint: Use try-except.

find_key(dictt, key): takes dictionary and key and prints value corresponding to the key from the dictionary: print("Value: ", value). If key is not found, then prints: "Key not found." Hint: Use try-except

Example:

Menu:

add(a), remove(r), find(f): a

Key: rich

Value: 1

More (y/n)? y
Menu:

add(a), remove(r), find(f): a

Key: alireza

Value: 2

More (y/n)? n
[('alireza', '2'), ('rich', '1')]

Example 2:

Menu:

add(a), remove(r), find(f): a

Key: pranshu

Value: 1

More (y/n)? y
Menu:

add(a), remove(r), find(f): r

key to remove: enbody
No such key exists in the dictionary.

More (y/n)? n

code

#add_to_dict() goes here:

#remove_from_dict() goes here

#find_key() goes here

def main():
more = True
dictt = {}
dictlst = []
while more:
print("Menu: ")
choice = input("add(a), remove(r), find(f): ")
if choice. lower() == "a":
key = input("Key: ")
value = input("Value: ")
dictt = add_to_dict(dictt, key, value)
elif choice. lower() == "r":
key = input("key to remove: ")
dictt = remove_from_dict(dictt, key)
elif choice. lower() == "f":
key = input("Key to locate: ")
find_key(dictt, key)
else:
print("Invalid choice.")

do_more = input("More (y/n)? ")
if do_more. lower() != 'y':
more = False
if dictt:
for key, value in dictt. items():
temp = (key, value)
dictlst. append(temp)
print(sorted(dictlst))
main()