Given the following function: void calc (int a, int& b) { int c; c = a + 2; a = a * 3; b = c + a; } What is the output of the following code segment that invokes calc(): int x = 1; int y = 2; int z = 3; calc(x, y); cout << x << " " << y << " " << z << endl;

The output is 1 6 3

x = 1

y = 6

z = 3

Explanation:

From the code snippet given; x and y is passed into the calc function. z is not passed to the function; so the value of z remain unchanged.

When x and y is passed to the calc function; the code execution as follows:

void calc (int a, int& b) { int c; c = a + 2; a = a * 3; b = c + a; }

void calc(1, 2){ int c; c =1 + 2; x = 1 * 3; y = 3 + 3;}

void calc(1, 2){c = 3; x = 3; y = 6;}

Inside the function, x = 3 but the value of x returned is 1 because of scoping. x is static while y is dynamic.

this seems to be in the wrong category. but i'll take some free points my dude

posting this in wrong category will result in people seeing it who won't know the answer.