Suppose that a disk drive has 2,000 cylinders numbered 0 to 1999. The drive is currently serving a request at cylinder 142, and the previous request was at cylinder 125. The queue of pending requests in FIFO order is:

86, 1470, 913, 1774, 948, 1509, 1022, 1750, 130.

Starting from the current head position, what is the total distance (in cylinders) that the disk arm moves to satisfy all the pending requests for the following disk scheduling algorithm FCFS.

Please answer immediately

Please answer it’s due tonight

Please someone answrr

7080

Explanation:

Let initial seek distance be= 0

Then,

    142-86=56                  a=56

     1470-86=1384                      a= 56+ 1384=1440

     1470-913= 557             a= 1440+557= 1997

     1774-913=861                    a= 1997+ 861=2858

     1774-948= 826              a=2858+826=3684

     1509-948=561             a=3684+561=4245

     1509-1022=    487        a=4245+487=4732

     1750-1022=728          a=4732+728=5460

     1750-130=1620          a=5460+1620=7080

      hence, Net distance in cylinders= 7080

And this is the overall seek distance.