THE bestValue PROBLEM Using the Camera structure defined in file p1.cpp, write the function named bestValue(). The function takes one input parameter: a vector of Camera. The vector is sorted by manufacturer, so all cameras of a particular manufacturer are together in the vector. The function returns a vector of string, with the manufacturer, model number and price concatenated together exactly in this format.

#include <iostream>

#include <vector>

#include <string>

#include <cmath>

#include <iomanip>

#include <sstream>

using namespace std;

// Given struct

struct Camera {

// Declaring variables

string manufacturer;

string model;

int releaseYear;

int resolution;

int weight;

double price;

};

vector<string> bestValue(const vector<Camera>& cameraNew) {

vector<string> display;

double winnerOne = 0;

double winnerTwo = 0;

double realWinnerOne = 0;

double realWinnerTwo = 0;

string displayOne;

string displayTwo;

string ans;

int find = 0;

// Calculating best value using given formula

for (unsigned i = 1; i < cameraNew.size(); i++) {

winnerOne = cameraNew[i].price / static_cast<double>(cameraNew[i].resolution);

winnerTwo = cameraNew[i-1].price / static_cast<double>(cameraNew[i - 1].resolution);

if (cameraNew[i].manufacturer == cameraNew[i - 1].manufacturer) {

if (winnerOne > winnerTwo && winnerOne > realWinnerOne) {

find = 1;

}

else if (winnerOne < winnerTwo && winnerTwo > realWinnerTwo) {

find = 2;

}

if (find == 1) {

realWinnerOne = cameraNew[i].price/ static_cast<double>(cameraNew[i].resolution) ;

ostringstream displayStream1;

displayStream1 << fixed << setprecision(2) << cameraNew[i].price;

displayOne = cameraNew[i].manufacturer + ":" + cameraNew[i].model + ":$" + displayStream1.str();

find = 0;

}

else if (find == 2) {

realWinnerTwo = cameraNew[i - 1].price / static_cast<double>(cameraNew[i - 1].resolution);

ostringstream displayStream2;

displayStream2 << fixed << setprecision(2) << cameraNew[i - 1].price;

displayTwo = cameraNew[i-1].manufacturer + ":" + cameraNew[i-1].model + ":$" + displayStream2.str();

find = 0;

}

}

else {

if (realWinnerOne >= realWinnerTwo) {

display.push_back(displayOne);

realWinnerOne = 0;

realWinnerTwo = 0;

}

else if (realWinnerOne < realWinnerTwo) {

display.push_back(displayTwo);

realWinnerOne = 0;

realWinnerTwo = 0;

}

}

}

if (realWinnerOne > realWinnerTwo) {

display.push_back(displayOne);

}

else if (realWinnerOne < realWinnerTwo) {

display.push_back(displayTwo);

}

else if (realWinnerOne == realWinnerTwo) {

display.push_back(displayTwo);

}

return display;

}

template <typename T>

ostream& operator<<(ostream& out, const vector<T>& display) {

if (display.size() > 0) {

out << "0. " << display[0];

out << endl;

//displaying output in the given format

for (size_t i = 1; i < display.size(); i++) {

out << i << ". " << display[i];

out << endl;

}

}

else

{

out << "Size of the vector is 0 or less than 0." << endl;

}

return out;

}

void camBestValue() {

const vector<Camera> vCameras = {

{ "Agfa", "ePhoto 1280", 1996, 1024, 400, 180 },

{ "Agfa", "ePhoto CL45", 2000, 1600, 275, 180 },

{ "Canon", "PowerShot 350", 1996, 640, 315, 150 },

{ "Canon", "PowerShot 600", 1994, 832, 445, 139 },

{ "Canon", "PowerShot A10", 2001, 1280, 355, 139 },

{ "Casio", "Exilim EX-P505", 2005, 2560, 250, 260 },

{ "Casio", "Exilim EX-P600", 2006, 2816, 275, 260 },

{ "Casio", "Exilim EX-P700", 2006, 3072, 275, 260 },

{ "Epson", "PhotoPC 800", 1997, 1600, 285, 220 },

{ "Epson", "PhotoPC L-500V", 2004, 2560, 205, 150 },

{ "Fujifilm", "FinePix 40i", 2000, 2400, 185, 180 },

{ "Fujifilm", "FinePix 50i", 2001, 2400, 205, 180 },

{ "Fujifilm", "DS-260HD", 1997, 1280, 845, 190 },

{ "Fujifilm", "DS-300", 1995, 1280, 845, 200 },

{ "HP", "Photosmart 320", 2002, 1632, 230, 190 },

{ "HP", "Photosmart 435", 2003, 2048, 180, 190 },

{ "HP", "Photosmart 620", 2002, 1632, 260, 190 },

};

vector<string> display;

display = bestValue(vCameras);

cout << display << endl;

}

int main() {

camBestValue();

}

Explanation:

The program takes one input parameter: a vector of Camera. The vector is sorted by manufacturer, so all cameras of a particular manufacturer are together in the vector.

The function returns a vector of string, with the manufacturer, model number and price concatenated together.

It produces the best value.

you go to add your answer type bewteen 5000 and 20 characters and can only have 2 people answer on 1 question.your challanges are based on your questions.

answer; ///400 ibs;