Write a function get_common_elems(lst1, lst2) that takes two lists of integers, lst1, and lst2, and returns a new list containing the elements in common between the two lists. You can assume that there are no repeated elements in the lists. Also, the ordering of the elements in the returned new list is not significant. The function signature is given below: def get_common_elems(lst1,lst2): sig : list (int),list (int) -> list(int) For example, a call to get_common_elems([5,1,4,3,6],[6,1,8 ,3]) will return the list 1, 3, 6. Hint: Think about how you can make use of the in operator. You only need to iterate over one of the lists.

Write a full class definition for a class named player , and containing the following members: a data member name of type string .a data member score of type int .a member function called setname that accepts a parameter and assigns it to name . the function returns no value.a member function called setscore that accepts a parameter and assigns it to score . the function returns no value.a member function called getname that accepts no parameters and returns the value of name .a member function called getscore that accepts no parameters and returns the value of score .this is what i have, aparently this is wrong: class player{private: string name; int score; public: void player: : setname (string n){name =n; }void player: : setscore (int s){score = s; }string player: : getname (){return name; }int player: : getscore (){return score; }};

Select the correct answer. which step can possibly increase the severity of an incident? a. separating sensitive data from non-sensitive data b. immediately spreading the news about the incident response plan c. installing new hard disks d. increasing access controls

4. does the kernel phenotype distribution support the idea that the cob is the result of a dihybrid cross? what information supports your answer? if a dihybrid cross (i.e. f1 to f2 of standard mendelian crosses) is not indicated what conditions might contribute to this finding.