subject

1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s3 with compareTo(), print out which string (s2 or s3) is greater than which string (s2 or s3), or equal, print the result out 4. Use the regionMatches to compare s2 and s3 with case sensitivity of the first 8 characters and print out the result (match or not) . 5. Find the location of the first character 'g' in s1, print it out 6. Find the last location of the substring "class" from s2, print it out

ansver
Answers: 2

Another question on Computers and Technology

question
Computers and Technology, 22.06.2019 17:00
Acase study allows a more detailed look at the life of a single subject than any other study.
Answers: 3
question
Computers and Technology, 23.06.2019 04:00
Write a method that takes in an array of point2d objects, and then analyzes the dataset to find points that are close together. be sure to review the point2d api. in your method, if the distance between any pair of points is less than 10, display the distance and the (x,y)s of each point. for example, "the distance between (3,5) and (8,9) is 6.40312." the complete api for the point2d adt may be viewed at ~pf/sedgewick-wayne/algs4/documentation/point2d.html (links to an external site.)links to an external site.. try to write your program directly from the api - do not review the adt's source code.
Answers: 1
question
Computers and Technology, 23.06.2019 04:31
Selling a product through an electronic medium is
Answers: 1
question
Computers and Technology, 23.06.2019 15:30
The song about casey jones a railroad engineer who gives his life on the job would most likely gall under the folk song category of? a-work song b-nonsense song c-religious song d-ballad
Answers: 1
You know the right answer?
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reve...
Questions
question
Mathematics, 19.11.2019 05:31
question
Mathematics, 19.11.2019 05:31
question
Mathematics, 19.11.2019 05:31
Questions on the website: 13722367