The following numbers are inserted into a linked list in this order: 10, 20, 30, 40, 50, 60
What would the following statements display?
pCur = head->next;
cout << pCur->data << " ";
cout << pCur->next->data << endl;
a) 20 30
b) 40 50
c) 10 20
d) 30 40

A. 20 30

Explanation:

Given

Linked list: 10, 20, 30, 40, 50, 60

Required

The output of the following code segment

pCur = head->next;

cout << pCur->data << " ";

cout << pCur->next->data << endl;

A linked list operates by the use of nodes which begins from the head to the next node, to the next, till it reaches the last;

The first line of the code segment; "pCur = head->next; " shifts the node from the head to the next node

The head node is the node at index 0 and that is 10;

This means that the focus has been shifted to the next at index 1 and that is 20;

So, pCur = 20

The next line of the code segment; cout << pCur->data << " "; prints pCur and a blank space

i.e. "20 " [Take note of the blank space after 20]

The last line "cout << pCur->next->data << endl; " contains two instructions which are

1. pCur = next->data;

2. cout<<pCur->data;

(1) shifts focus to the next node after 20 ; This gives pCur = 30

(2) prints the value of pCur

Hence, the output of the code segment is 20 30

answer6-9 screws;