Steven, Marcos, and Juan are having a free-throw shooting contest. Each boy takes six turns and records the number of free throws he makes out of 10
shots. Which boy's median is greatest?
Steven: 2,4,6,8,8,9
Marcos: 3, 5, 6, 7, 8, 10
Juan: 3, 5, 5, 6,9,9

Steven

Explanation:

Given the data:

Steven: 2, 4, 6, 8, 8, 9

Marcos: 3, 5, 6, 7, 8, 10

Juan: 3, 5, 5, 6, 9, 9

The median value of an ungrouped data can be calculated or located using the relation:

Median observation = (n + 1) / 2

Whwre n) number of observations.

If a Decimal value is obtained, the upper and lower bound of the observation is averaged to obtain the median value.

Steven: 2, 4, 6, 8, 8, 9

(6 + 1) / 2 = 7/2 = 3.5

Therefore, the 3rd and 4th observations in the data is averaged.

Median = (6+8) / 2 = 14/2 = 7

Marcos: 3, 5, 6, 7, 8, 10

(6 + 1) / 2 = 7/2 = 3.5

Therefore, the 3rd and 4th observations in the data is averaged.

Median = (6+7) / 2 = 13/2 = 6.5

Juan: 3, 5, 5, 6,9,9

(6 + 1) / 2 = 7/2 = 3.5

Therefore, the 3rd and 4th observations in the data is averaged.

Median = (5+6) / 2 = 11/2 = 5.5

Therefore, Steven has the greatest median

8 track im pretty sure came first