Please help. it's java program
Question:
Without using if-else statement and ternary operators, accept numbers and display the second smallest number. Hint: Use Math. max() and Math. min() functions] Sample Input: 34, 82, 61

three unequal

Sample Output: 61

Hey mate!

import java.util.*;

class Max Min

{

public static void main()

{

int a,b,c,x,y,z,m,n;

Scanner in=new Scanner(System.in);

System.out.println("Enter three unequal numbers:");

a=in.nextInt();

b-in.nextInt();

c=in.nextInt();

x=Math.max(a,b);

y=Math.max(b,c);

z=Math.max(c,a);

m=Math.min(x,y);

n=Math.min(z,m);

System.out.printLn("Second Smallest Number is:"+n);

}

}

Explanation:

hope it helped you:)