10. Let the worst case propagation delay for a NOT gate be 10 ns (nanoseconds, 10-9 sec), for 2-input logic gates be 20 ns, for 3-input logic gates be 24 ns, and for 4-input logic gates be 28ns. From lecture slide 29 we have the Boolean SOP expression m = x’yz + x’yz’ + x’y’ + xyz and its simplified form m = x’ + xyz Assume that only the positive logic inputs x, y, and z are available, meaning that x’, for example, must be computed using a NOT gate if x’ is needed. How much less than that for the original expression is the worst case propagation delay for the simplified form?

Answer: this depends on the amount required to pay off the individual's card as well as how large the minimum payments are.if the amount is significantly large and the minimum payments are significantly small, then it will take a longer time to pay off the credit card.if the amount is significantly small and the minimum payments are significantly large, then it will take less time to pay off the credit card.hence, it would be difficult to answer true or false to this statment.however, for the purpose of this statement, it is most likely assumed that regardless of the amount to pay off the credit card the minimum payments would be quite large.therefore, the better option would be to pick 'true' as your answer.hope this ! : )have a lovely day! < 3

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