(Display characters) Write a method that prints characters using the following header: public static void printChars(char ch1, char ch2, int numberPerLine) This method prints the characters between ch1 and ch2 with the specified numbers per line. Write a test program that prints ten characters per line from 1 to Z. Characters are separated by exactly one space.

public class MyClass {

   public static void printChar(char ch1, char ch2, int numberPerLine){

       int i = 0;

       for (char c = ch1; c <= ch2; c++){

           while (i < numberPerLine){

               System.out.print(c + " ");

               i += 1;

           }

           System.out.println("");

           i = 0;

       }

   }

   public static void main(String args[]) {

     printChar('a', 'z', 10);

   }

}

So far, this works by printing letters. If you need me to modify the code, I will.

Written in Java

public static void printChars(char ch1, char ch2, int numberPerLine){

        int i = 1;

        for(char A = ch1; A <= ch2; A++){

            if(i<=numberPerLine){

               System.out.print(A+" ");    

               i++;

            }

            else{

                System.out.println();

                i = 1;

            }

        }

    }

Explanation:

This line defines the method

public static void printChars(char ch1, char ch2, int numberPerLine){

This line initializes the number of print out per line to 1

        int i = 1;

The following is an iteration that prints from ch1 to ch2. Note that ch1 and ch2 are characters

        for(char A = ch1; A <= ch2; A++){

The following if condition (italicized) checks if the number of print outs is up to the required length.

If No, the character is printed

If yes, a new line is printed.

           if(i<=numberPerLine){

               System.out.print(A+" ");    

               i++;

            }

            else{

                System.out.println();

                i = 1;

            }

        }

    }

See attachment for full program including test of ten characters in a line

a.s= 230t– 110; 1500 lbc.t= 230s– 110; 1500 lbb.s= 230t+ 110; 1720 lbd.s= 199t– 110; 1280 lb

answersecurity intrusion;