Tell me everything you know about parking barriers

Print "usernum1 is negative." if usernum1 is less than 0. end with newline. convert usernum2 to 0 if usernum2 is greater than 10. otherwise, print "usernum2 is less than or equal to 10.". end with newline

Johnson enterprises uses a computer to handle its sales invoices. lately, business has been so good that it takes an extra 3 hours per night, plus every third saturday, to keep up with the volume of sales invoices. management is considering updating its computer with a faster model that would eliminate all of the overtime processing.

Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }