Put the steps in order to produce the output shown below. Assume the indenting will be correct in the program. 2 3
2 5
6 3
6 5
Line 3
Line 1
Line 2
for numF in [3,5]:print (numE, numF)for numE in [2,6]:

Python indentation are used to group statements that belongs to the same block of code.

The correct steps are as follows:

for numE in [2,6]:

      for numF in [3,5]:

             print (numE, numF)

From the output of the program, we have the following highlights.

The above highlights mean that: the program iterates through list E, before iterating list F

So, the order of the program is:

for numE in [2,6]:

      for numF in [3,5]:

             print (numE, numF)

Read more about Python indentation at:

link

Code:

for numE in [2, 6]:

   for numF in [3, 5]:

      print(numE, numF)

Explanation:

Since the first number of the first output is 2, the outer loop must contain the list [2, 6], meaning 'for numE in [2, 6]:' is on line 1. This leaves us with 'for numF in list [3, 5]:' as the nested loop (line 2), and the print statement on line 3 since it needs to print both numE and numF.

Hope this helps :)

answer; ron will have to compare ( b3: b4); /// good luck

2b2t

explanation:

2b2t