Assume the configuration: A B C where A-B has an MTU of 2100 bytes and B-C has an MTU of 700 bytes. Assume that link layer frames require 30 bytes of overhead, an IP header is 20 bytes, there is no loss in the network, and A always tries to send full frames to C. For every packet that A sends, how many IP packets will cross the link from B to C? Group of answer choices 4 packets 3 packets 5 packets 6 packets

4 packets

Explanation:

Given that:

      MTU = 2100B            MTU = 700 B

A     B    C

Link A → T

For a packet, there are 2100B of data length in which header length = 50 B & payload = 2050B

Thus, this packet needs to be fragmented into packets for length = 700 B

where;

payload = 650 B

header = 50B

Therefore;

50║2050     →     50║650

                            50║650

                            50║650

                            50║100

Thus, for each packet A sent, 4 packets will cross the link from B to C.

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