What will be the output of the following code? import java. util. ArrayList;
public class arrayList7
{
public static void main(String[] args) {
ArrayList one = new ArrayList ();
Integer count=3;
count=count+1;
one. add(2);
one. add(count);
System. out. println(one. get(1));
}
}

The correct answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is : 4.

When you run this program in Java. The output produce by this program is 4

The given code is:

import java.util.ArrayList;

public class arrayList7

{

public static void main(String[] args) {

ArrayList one = new ArrayList ();

Integer count=3;

count=count+1;

one.add(2);

one.add(count);

System.out.println(one.get(1));

}

}

This code store the value in ArrayList one variable. It first adds 2 at zero indexes and 4 at first index.  When you print the value at index one, you will get the output 4. because the count variable contains 4. If you want to print 2, then you specify the print statement that prints the value at index zero. eg.

System.out.println(one.get(0));

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answer; i believe the answer you're looking for is (nanotechnology);