If u want to play amoung us the code is vnkgff , no free points for points guess my age

Define a class named movie. include private fields for the title,year, and name of the director. include three public functions withprototypes void movie: : settitle(cstring); , voidmovie: : setyear(int); , void movie: : setdirector(string); . includeanother function that displays all the information about a movie.write a main() function that declares a movie object namedmyfavoritemovie. set and display the object's fields.this is what i have but know its wrong since it will notcompile: #include#includeusing namespace std; //class declarationclass movie{private: string movietitle ; string movieyear; string directorname; public: void settitle(string title); void setyear(string year); void setdirector(string director); void displayinfo(); }; //class implementationvoid movie: : settitle(string title){ movietitle = title; cout< < "what is the title of themovie? "< > temp; myfavoritemovie.settitle(temp); cout< < "enter movie year"< > temp; myfavoritemovie.setyear(temp); cout< < "enter director'sname"< > temp; myfavoritemovie.setdirector(temp); //display all the data myfavoritemovie.displayinfo(); system("pause"); return 0; this code is not entirely mine someone on cramster edited my firstcode but then i try manipulating the new code and i still get acompile error message : \documents\visual studio 2008\projects\movie\movie\movie.cpp(46) : error c2679: binary '< < ' : no operator found which takes aright-hand operand of type 'std: : string' (or there is no acceptableconversion)c: \program files (x86)\microsoft visual studio9.0\vc\include\ostream(653): could be'std: : basic_ostream< _elem,_traits> & std: : operator< < > (std: : basic_ostream< _elem,_traits> & ,const char *)w

In cell h5 enter a formula that will calculate the percentage of attendees that went to the altamonte springs job fair in 2018.

4. does the kernel phenotype distribution support the idea that the cob is the result of a dihybrid cross? what information supports your answer? if a dihybrid cross (i.e. f1 to f2 of standard mendelian crosses) is not indicated what conditions might contribute to this finding.