Assume that x and y are boolean variables and have been properly initialized.(x && y) || !(x && y) The result of evaluating the expression above is best described as (A) always true (B) always false (C) true only when x is true and y is true (D) true only when x and y have the same value (E) true only when x and y have different values

(A) Always true

Explanation:

Given

Boolean variables x and y

Required

What is (x && y) || !(x && y)

Irrespective of what x or y is, the x && y is always true

Take for instance:

x = true;

y = true;

x&&y will also be true because the values of x and y were not altered

And this is true for whatever boolean value x or y assume

Having said that:

x&&y = true

So, the expression is analysed as follows:

(x && y) || !(x && y)

Substitute true for x&&y

(true) || !(true)

!(true) = false

So, the expression becomes:

true || false

|| represents the OR operator; and it returns true if at least one of the conditions is true.

By this:

true || false = true

Option (A) Always true answers the question.

the printer can be used in a both wired and wireless network, only one of the connection methods can be used at one time when the wireless setting is enabled, the wired (ethernet) setting is disabled.

but first you need to

`connect the cord to your computer

`open settings app from the start menu

`click devices

`than click add printer or scanner

and than you should be able to do it from there, if not let me know i can you! : )