A drink costs 2 dollars. A taco costs 3 dollars. Given the number of each, compute total cost and assign totalCost with the result. Ex: 4 drinks and 6 tacos yields totalCost of 26. */
int main() {
int numDrinks = 0;
int numTacos = 0;
int totalCost = 0;
numDrinks = 4;
numTacos = 6;
/* Your solution goes here */
totalCost = (2 * numDrinks) + (3 * numTacos);
cout << "Total cost: " << totalCost << endl;
return 0;
}

Computing the total cost using code can be represented as follows:

def total_cost(no_of_drinks, no_of_talcos):

  totalCost = 2*no_of_drinks + 3*no_of_talcos

  return totalCost

print(total_cost(4, 6))

A function named total_cost is declared and it accept the parameters no_of_drinks and no_of_talcos.

The totalCost is used to store the result of the cost of the total drinks and tacos bought in dollars.

Then, we return the totalCost.

Finally, we use the print statement to call the function with its required parameters.

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See Explanation

Explanation:

The question has been answered; however, the program is not dynamic enough because the output will always be 26.

To make it dynamic, replace the following lines of code:

numDrinks = 4;

numTacos = 6;

with:

cout<<"Number of drinks: ";

cin>>numDrinks;

cout<<"Number of Tacos: ";

cin>>numTacos;

The above lines of code will let the user input different values for numDrinks and numTacos each time the program is executed.