The janitor of a high school is extremely efficient. By the end of each day, all of the school's waste is in plastic bags weighing between 1.01 pounds and 3.00 pounds. All plastic bags are then taken to the trash bins outside. One trip is described as selecting a number of bags which together do not weigh more than 3.00 pounds, dumping them in the outside trash can and returning to the school. Given the number of plastic bags n, and the weights of each bag, determine the minimum number of trips the janitor has to make. For example, given n = 6 plastic bags weighing weight = [1.01, 1.99, 2.5, 1.5, 1.01], the janitor can carry all of the trash out in 3 trips: [1.01 + 1.99 , 2.5, 1.5 + 1.01]. Write a java program to implement efficient janitor and explain the time complexity of your code.

Create a class named majors that includes an enumeration for the six majors offered by a college as follows: acc, chem, cis, eng, his, phys. display the enumeration values for the user, then prompt the user to enter a major. display the college division in which the major falls. acc and cis are in the business division, chem and phys are in the science division, and eng and his are in the humanities division. save the file as majors.java.

For a typical middle-income family, what is the estimated cost of raising a child to the age of 18? $145,500 $245,340 $304,340 $455,500

The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk,thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\