Which option is better? Option 1:
double d1 = 0.1; double d2 = 0.2; double d3 = 0.3; double x = (d1 + d2) + d3 ; double y = d1 + (d2 + d3); if (x == y) {System. out. println("Equal");}

Option 2:
double d1 = 0.1; double d2 = 0.2; double d3 = 0.3; double x = (d1 + d2) + d3 ; double y = d1 + (d2 + d3); double z = x - y; double epsilon = 1E-5; if (java. lnag. Math. abs(z) < epsilon) {System. out. println("Equal");}

i think option 2 is correct answer

Explanation:

op

answer

option a)the former is primarily for third party access to data

.is the correct answer.

key escrow can be characterized as course of action in which the keys expected to break   data are held bonded for some   circumstances and an approved outsider may access those keys.  

while recuperation specialists are the individuals who us in recuperation   of cash or different things.

add the following