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1. Considera a molécula de carbonato de cálcio (CaCO3). Ar(Ca)=40; Ar(C)=12; Ar(0) = 16; Ar(Cl) = 35; Ar(H) = 1 ; Ar(S) = 32
a) Calcula a sua massa molecular relativa.
b) Qual é a sua massa molar?
c) O que significa dizer que a massa molar do carbonato de cálcio é de 140 g/mol?
d) Qual é a massa de 3,8 mol de CaCO3.​

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1. Considera a molécula de carbonato de cálcio (CaCO3). Ar(Ca)=40; Ar(C)=12; Ar(0) = 16; Ar(Cl) = 3...
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