Computers and Technology, 04.03.2021 20:20 Silkyruthie

Programming Project ( Java ) You learned that computers follow instructions faithfully and they never get tired of repeating the same thing over and over. You plan to write a simple program Calculator. java to see for yourself.
After bragging a bit, the program asks the user to enter 2 numbers. After receiving and storing those it asks the user to enter one of the operations +,-, , or /. The program then performs that operation on the two numbers and displays the output to the user (if the user enters an operation different from the four operations above, the program notifies the user that it does not know that operation). It then brags some more and asks the user if they want to play again. If the user enters Y or y, the game starts over. Otherwise the program prints Bye bye and terminates.
A few sample runs of the program are shown below:
Run 1
Hi, I am really good at math! Put me to the test.
Please enter two numbers and then press Enter: 3 6
Please enter one of the operations +, -, or / and press Enter: +
3 + 6 = 9
I'm great at addition!
Play again [Y/N]?: N
Bye bye!
Run 2
Hi, I am really good at math! Put me to the test.
Please enter two numbers and then
press Enter: 2.7 0.82
Please enter one of the operations +,-, * or / and press Enter: -
2.7 - 0.82 = 1.88
I'm great at subtraction!
Play again [Y/N]?: N
Bye bye!
Run 3
Hi, I am really good at math! Put me to the test.
Please enter two numbers and then press Enter: 1 3
Please enter one of the operations +,-, * or / and press Enter: /
1 / 3 = 0.333333
I'm great at division!
Play again [Y/N]?: Y
Hi, I am really good at math! Put me to the test.
Please enter two numbers and then press Enter: 3.14 2
Please enter one of the operations +,-, * or / and press Enter: *
3.14 * 2 = 6.28
I'm great at multiplication!
Play again [Y/N]?: y
Hi, I am really good at math! Put me to the test.
Please enter two numbers and then press Enter: 2 3
Please enter one of the operations +,-, * or / and press Enter: $
I can compute really well, but what you entered is not one of the operations I know ...
Play again [Y/N]?: N
Bye bye!
Hints:
– This program is really simple and many of you will find it trivial. The goal of the assignment is for students to get familiar with their development tool, basic program design and the basic structure of a Java program. You should know almost all of what you need from your CS 50 course.
– The program uses 4 variables, two for the numeric values, one for the operation, and one for playing again or terminating. What type should these variables be?
– To be able to perform a different computation based on the operation entered the program will need to make a choice.
– Write the program initially without the "Play again?" functionality. Once you have that, wrap a loop around it to allow for repeated games.

Answers: 1

Show answers

Another question on Computers and Technology

Computers and Technology, 22.06.2019 06:30

This technology is used to produce high-quality documents that look good on the computer screen and in print. wiki presentation paint desktop publishing

Answers: 3

Answer

Computers and Technology, 22.06.2019 10:00

When is an original work considered public domain? a. when posted via social media b. when it is posted on the internet c. when a copyright symbol is not included with the piece of work d. when explicit permission is given by the author / owner

Answers: 1

Answer

Computers and Technology, 22.06.2019 11:10

Look at the far left lane in the picture. explain what the red car is doing and what it needs to do to travel safely.

Answers: 2

Answer

Computers and Technology, 22.06.2019 20:00

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }

Answers: 3

Answer

You know the right answer?

Programming Project ( Java ) You learned that computers follow instructions faithfully and they nev...

Questions