KDS Company has 3 departments: 1. Dept X 2. Dept Y 3. Dept Z. Design a program that will read as input each department's sales for each quarter of the year, and display the result for all divisions. Use a two dimensional array that will have 3 rows and 4 columns and show how the data will be organized.

In C++:

#include<iostream>  

using namespace std;  

int main() {  

  int depts[3][4];

  char dptcod [3] ={'X','Y','Z'};

  for (int rrw = 0; rrw < 3; rrw++) {  

      for (int cll = 0; cll < 4; cll++) {  

          cout<<"Dept "<<dptcod[rrw]<<" Q"<<(cll+1)<<": ";

          cin>>depts[rrw][cll];  }  }  

      for (int rrw = 0; rrw < 3; rrw++) {  

          int total = 0;

          for (int cll = 0; cll < 4; cll++) {  

              total+=depts[rrw][cll]; }

              cout<<"Dept "<<dptcod[rrw]<<" Total Sales: "<<total<<endl;}  

  return 0; }

Explanation:

This declares the 3 by 4 array which represents the sales of the 3 departments

  int depts[3][4];

This declares a character array which represents the character code of each array

  char dptcod [3] ={'X','Y','Z'};

This iterates through the row of the 2d array

  for (int rrw = 0; rrw < 3; rrw++) {  

This iterates through the column

      for (int cll = 0; cll < 4; cll++) {

This prompts the user for input

          cout<<"Dept "<<dptcod[rrw]<<" Q"<<(cll+1)<<": ";

This gets the input

          cin>>depts[rrw][cll];  }  }  

This iterates through the row of the array

      for (int rrw = 0; rrw < 3; rrw++) {

This initializes total sum to 0

          int total = 0;

This iterates through the column

          for (int cll = 0; cll < 4; cll++) {

This calculates the total sales of each department

              total+=depts[rrw][cll]; }

This prints the total sales of each department

              cout<<"Dept "<<dptcod[rrw]<<" Total Sales: "<<total<<endl;}  

I hope this helps a little bit

i belive the answer you are looking for is d: the nether