Computers and Technology, 13.04.2021 01:00 nakeytrag

Research the functionality of the three layers (presentation, domain, and data source) of enterprise application software. Write a paper describing each layer in detail as it would apply to a specific type of enterprise application software (you select the specific type of software to use in your examples, be consistent and use the same type of enterprise application software through your entire paper). Be sure to introduce the type of enterprise application software you have selected to use as an example. Point out areas that could be problematic in the development cycle for the specific example that you have selected as well as solutions that you deem appropriate.

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Answer from: Quest

the answer is c

Answer from: Quest

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Answer from: Quest

The answer is c. 36======analyzing the for-loop, we see that the control variable, k, starts at 0 and increments by after every loop iteration. the condition $\texttt{k\ \textless \ =7}$ tells us that the loop will stop when k is above 7; in this case, when k is 8.0 1 2 3 4 5 6 7 are the values for k that will be used. each number is for each iteration; therefore, the for-loop will have 8 iterations in total.the code inside the loop itself goes like this: 1st iteration (k=0)starting with sum=0, val=1 $\texttt{sum += val; }$ means that add $\texttt{val}$ to $\texttt{sum}$ .since sum is 0 and val is 1, 0 + 1 = 1. the new value of sum is 1. $\texttt{val++; }$ means to increment $\texttt{val}$ by 1.since val is 1, the new value of val of 2.end of iteration with k=0; k is increased by one to become k=12nd iteration (k=1)starting with sum=1, val=2 $\texttt{sum += val; } \iff \texttt{sum = 1 + 2}$ ======let us establish a pattern. this is moreso logic than programming: we can rewrite $\texttt{sum = 1 + 2}$ so that we have the elements from the previous iteration. the 1 came from 0 + 1 before. so we can write it as $\texttt{sum = 0 + 1 + 2}$ .and if we did the third iteration, by the end, sum would look like $\texttt{sum = 0 + 1 + 2 + 3}$ notice how the number of plus signs is equal to the iteration you are on (which is just k+1), and what is being added is increasing by one each time. for example, the third iteration (k=2) ends up with $\texttt{sum = 0 + 1 + 2 + 3}$ with 3 plus signs.the second iteration (k=1) ends up with $\texttt{sum = 0 + 1 + 2}$ with two plus signs.the first iteration (k=0) ends up with $\texttt{sum = 0 + 1}$ with one plus sign.this is a pattern. the nth iteration will have n plus signs.since we established before that there are 8 iterations of this loop in total, the value of sum at k=7 (the 8th and last iteration) will have sum with 8 plus signs. $\begin{aligned} \texttt{sum} & = \texttt{0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{3 + 3 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{6 + 4 + 5 + 6 + 7 + 8 } \\ & = \texttt{10 + 5 + 6 + 7 + 8 } \\ & = \texttt{15 + 6 + 7 + 8 } \\ & = \texttt{21 + 7 + 8 } \\ & = \texttt{28 + 8 } \\ & = \texttt{36} \end{aligned}$ so the value of sum at the end of the loop is 36.

Answer from: Quest

explanationyou can cause an accident, spilling your beverage may break your computer. eating food etc, may cause crumbs to enter the keyboard jamming a key and it may cause it not to work. cand maybe. depends on what candy.

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Research the functionality of the three layers (presentation, domain, and data source) of enterprise...