Assign true to the variable has_dups if the string s1 has any duplicate character (that is if any character appears more than once) and false otherwise.

here is the answer i wrote:

i = []
for i in range(len([s1])):
if s1.count(s1[i]) > 1:
has_dups = true
elif s1.count(s1[i]) = 1:
has_dups = false

here is the message i got from the system:

solutions with your approach don't usually use: elif

me to correct it.

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Write the command that can be used to answer the following questions. (hint: try each out on the system to check your results.) a. find all files on the system that have the word test" as part of their filename. b. search the path variable for the pathname to the awk command. c. find all files in the /usr directory and subdirectories that are larger than 50 kilobytes in size. d. find all files in the /usr directory and subdirectories that are less than 70 kilobytes in size. e. find all files in the / directory and subdirectories that are symbolic links. f. find all files in the /var directory and subdirectories that were accessed less than 60 minutes ago. g. find all files in the /var directory and subdirectories that were accessed less than six days ago. h. find all files in the /home directory and subdirectories that are empty. i. find all files in the /etc directory and subdirectories that are owned by the group bin."