Anyone seen by the camera, whether or not they have a speaking part or any other significant role in the program, is considered the?

Jane’s team is using the v-shaped model for their project. during the high-level design phase of the project, testers perform integration testing. what is the purpose of an integration test plan in the v-model of development? a. checks if the team has gathered all the requirements b. checks how the product interacts with external systems c. checks the flow of data in internal modules d. checks how the product works from the client side

Write a full class definition for a class named player , and containing the following members: a data member name of type string .a data member score of type int .a member function called setname that accepts a parameter and assigns it to name . the function returns no value.a member function called setscore that accepts a parameter and assigns it to score . the function returns no value.a member function called getname that accepts no parameters and returns the value of name .a member function called getscore that accepts no parameters and returns the value of score .this is what i have, aparently this is wrong: class player{private: string name; int score; public: void player: : setname (string n){name =n; }void player: : setscore (int s){score = s; }string player: : getname (){return name; }int player: : getscore (){return score; }};

Me with this program in c++ ! computers represent color by combining sub-colors red, green, and blue (rgb). each sub-color's value can range from 0 to 255. thus (255, 0, 0) is bright red. (130, 0, 130) is a medium purple. (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (in other word, equal amounts of red, green, blue yield gray).given values for red, green, and blue, remove the gray part. ex: if the input is 130 50 130, the output is: 80 0 80. thus, find the smallest value, and then subtract it from all three values, thus removing the gray.