Working with do-while loop Bring the program dowhile. cpp from the Lab 5 folder.
The code is shown below:

// This program displays a hot beverage menu and prompts the user to
// make a selection. A switch statement determines which item the user
// has chosen. A do-while loop repeats until the user selects item E
// from the menu.
// PLACE YOUR NAME HERE
#include
#include
using namespace std;
int main()
{
// Fill in the code to define an integer variable called number,
// a floating point variable called cost,
// and a character variable called beverage
bool validBeverage;
cout << fixed << showpoint << setprecision(2);
do
{
cout << endl << endl;
cout << "Hot Beverage Menu" << endl << endl;
cout << "A: Coffee $1.00" << endl;
cout << "B: Tea $ .75" << endl;
cout << "C: Hot Chocolate $1.25" << endl;
cout << "D: Cappuccino $2.50" << endl < cout << "Enter the beverage A, B,C, or D you desire" << endl;
cout << "Enter E to exit the program" << endl << endl;
// Fill in the code to read in beverage
switch(beverage)
{
case 'a':
case 'A':
case 'b':
case 'B':
case 'c':
case 'C':
case 'd':
case 'D': validBeverage = true;
break;
default: validBeverage = false;
}
if (validBeverage == true)
{
cout << "How many cups would you like?" << endl;
// Fill in the code to read in number
}
// Fill in the code to begin a switch statement
// that is controlled by beverage
{
case 'a':
case 'A': cost = number * 1.0;
cout << "The total cost is $ " << cost << endl;
break;
// Fill in the code to give the case for tea ( $0.75 a cup)
//Fill in the code to give the case for hot chocolate($1.25 a cup)
// Fill in the code to give the case for cappuccino ($2.50 a cup)
case 'e':
case 'E': cout << " Please come again" << endl;
break;
default:cout << // Fill in the code to write a message
// indicating an invalid selection.
cout << " Try again please" << endl;
}
} // Fill in the code to finish the do-while statement with the
// condition that beverage does not equal (E or e).
// Fill in the appropriate return statement
}