Write a function wordcount() that takes the name of a text file as input and prints the number of occurrences of every word in the file. You function should be case-insensitive so 'Hello' and 'hello' are treated as the same word. You should ignore words of length 2 or less. The results printed will be ordered from the most frequent to the least frequent. Hint: dictionary and list. Test your implementation on file great_expectations. txt

Explanation:

The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.

import re

def wordCount(fileName):

   file = open(fileName, 'r')

   wordList = file.read().lower()

   wordList = re.split('\s', wordList)

   wordDict = {}

   for word in wordList:

       if word in wordDict:

           wordDict[word] = wordDict.get(word) + 1

       else:

           wordDict[word] = 1

   print(wordDict)

wordCount('great_expectations.txt')

answer: a, c

divide any of the y values by x values and you will always get 3 is the most simple way i can put it for you.

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