Write a program using a dictionary that reads in a single positive digit number [0 - 9] from the user at the keyboard. Your program will then be able to look up the digit key in the dictionary and print the digit value spelled out. If the user types in a number that is either more than one digit, negative, or a non int value, re-prompt the user for valid input. First, before demonstrating your test cases, print out a display copy of the key:value pairs in your dictionary in sorted order. Deliverable: yournameLab4.py Your source code solution and a copy of the run pasted into your source submission file. Be sure to comment out your run so that your .py file will still run in the grader test bed. Validate user input is a single positive digit [0 - 9].

The program in Python is as follows:

dict = {0:"Zero",1:"One",2:"Two",3:"Three",4:"Four",5:"Five",6:"Six",7:"Seven",8:"Eight",9:"Nine"}

num = input("Number: ")

while(num.isdigit() == False or int(num)<0 or int(num)>9):

   num = input("Number: ")

print(dict)    

print(dict[int(num)])

Explanation:

#This initializes the dictionary

dict = {0:"Zero",1:"One",2:"Two",3:"Three",4:"Four",5:"Five",6:"Six",7:"Seven",8:"Eight",9:"Nine"}

#This gets input from the user

num = input("Number: ")

#This loop is repeated until the user enters a valid input

while(num.isdigit() == False or int(num)<0 or int(num)>9):

   num = input("Number: ")

#This prints the dictionary

print(dict)    

#This prints the value of the key

print(dict[int(num)])

See attachment for sample run

answer; /// i believe ist (al shugart);

its true for the one time