The process address space is composed of five segments: TEXT, DATA, BSS, HEAP, and STACK. You have to tell in what segment you will place each one of the following examples. a. int nodesize;
b. malloc(nodeSize);
c. nodesize = 6; -CU
d. nodesize = 20;
e. int nodesize = 2;

Will this setup result in what kathy wants to print?

Consider the usual algorithm to convert an infix expression to a postfix expression. suppose that you have read 10 input characters during a conversion and that the stack now contains these symbols: (5 points) | | | + | | ( | bottom |_*_| now, suppose that you read and process the 11th symbol of the input. draw the stack for the case where the 11th symbol is

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