Researchers endeavoring to conduct an online study

This problem has been solved! see the answeran evil king has a cellar containing n bottles of expensive wine, and his guards have just caught a spy trying to poison the king’s wine. fortunately, the guards caught the spy after he succeeded in poisoning only one bottle. unfortunately, they don’t know which one. to make matters worse, the poison the spy used was very deadly; just one drop diluted even a billion to one will still kill someone. even so, the poison works slowly; it takes a full month for the person to die. design a scheme that allows the evil king to determine exactly which one of his wine bottles was poisoned in just one month’s time while expending at most o(logn) of his taste testers.you are not allowed to use n testers, one for each bottle, and see which one tester dies after 30 days.(no pseudocode needed. just answer in words, how many testers you use, how you use them and why you correctly identify the poisoned bottle in 30 days)

Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". any value that is the same as the immediately preceding value is considered a consecutive duplicate. in this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. note that the last 3 is not a consecutive duplicate because it was preceded by a 7. write some code that uses a loop to read such a sequence of non-negative integers , terminated by a negative number. when the code finishes executing, the number of consecutive duplicates encountered is printed. in this case, 3 would be printed. assume the availability of a variable, stdin, that references a scanner object associated with standard input. that is, stdin = new scanner(system.in); is given.

How to print: number is equal to: 1 and it is odd number number is equal to: 2 and it is even number number is equal to: 3 and it is odd number number is equal to: 4 and it is even number in the console using java using 1 if statement, 1 while loop, 1 else loop also using % to check odds and evens