Using powerpoint 2016, ethan develops a short five-slide presentation for his marketing project. â â powerpoint files consist of what looks like pages in a document. ethan correctly calls these buttons a. groups b. ribbons c. slides d. banners

Acomputer has a two-level cache. suppose that 60% of the memory references hit on the first level cache, 35% hit on the second level, and 5% miss. the access times are 5 nsec, 15 nsec, and 60 nsec, respectively, where the times for the level 2 cache and memory start counting at the moment it is known that they are needed (e.g., a level 2 cache access does not even start until the level 1 cache miss occurs). what is the average access time?

Install and use wireshark program ( send back screen shots and other vital information) case project 3-2: decode a tcp segment in a wireshark capture in this chapter, you walked through tcp segment to interpret the data included in its header. in this project, you use wireshark to capture your own http messafes, examine the tcp headers, and practice interpreting the data you'll find there. 1. open wireshark and snap the window to one side of your screen. open a browser and snap that window to the other side of your screen so you can see both windows.

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?