What is the resistance of a light bulb that uses 15 watts of power when placed across a 15-volt battery

The power dissipated by a single component is

                     Power  =  (voltage²) / (resistance) .

Multiply each side by resistance: 

                     Power x resistance  =  voltage²

Divide each side by Power:

                         Resistance  =  voltage² / power

                                             =  (15V)² / (15W)

                                             =  225 V² / (15 volt-amp)

                                             =  15 volt/amp  =  15 ohms .

Ithink it’s c. 1 pm and 3 pm

Answer(d) readers name,your name,the date,the subject,and the body of the memo;