Find the dimensions of a circular cross section steel bar subjected to tension by a force n 2 n in two hypotheses: a) the maximum allowable stress is 150 n/mm2, b) the maximum acceptable strain is 0.0005. take e 207gpa

d = 13 mm

d =  15.68 mm

Explanation:

Given data

force = 20000 N

stress = 150 N/mm²

strain = 0.0005

E = 207 GPa

Solution

we know stress = force / area

so 0.0005 = 20000 / area

area = /4 × d²

put the area in stress equation and find out d

d² = 4×force / ×stress

d² = 4× 20000 / ×150

d = ×150}" alt="\pi" /> ×150}" />

d = 13 mm

and now we know starin = stress / E

same like stress we find d here

d = ×0.0005×207×10³ }" alt="\pi" /> ×0.0005×207×10³ }" />

so d =  15.68 mm

answer:

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explanation: