The specific heat of aluminum is approximately 900 j/kg°c. if the temperature of a 5 kg specimen needs to be raised from 30°c to 1000°c, the amount of heat required will be equal to select one: a)- 4365 kj b)- 4365 btu c)- 4365w d)- none of the above

a) 4365 kJ

Explanation:

In any thermodynamic system, any heat change is accompanied by the change in temperature.  The relation between heat released/gained in a system and the temperature is:

Q=mcΔT

where,

Q is the amount of heat absorbed or released

m is the mass

ΔT is the change in temperature

c is called the specific heat.  

Specific heat is defined as heat gained by 1 unit mass of any sample to raise the temperature of the sample by 1 °Celsius.

Thus, from the question:

Mass of aluminum =5 kg

Final temperature = 1000°C

Initial temperature = 30°C

ΔT = (1000 -30)°C = 970°C

Specific heat of aluminum = 900 J/kg°C

Thus, Amount of heat required:

Q = 5 kg×900 J/kg°C×970°C = 4365000 J

The conversion of J into kJ is shown below:

1 J = 10⁻³ kJ

Thus,  Heat gained by aluminum =4365000 ×10⁻³ J = 4365 kJ

no he didnt use it

explanation:

he said no