Awooden block (sg = 0.6) floats in oil (gs = 0.8). what fraction of the volume of the block is submerged in oil?

3/4 th fraction of the volume of block is submerged in oil.

Explanation:

We know that

density of the block, ρ =SGdensity of water

                                                           = 0.6 1000

                                                           = 600 kg/

density of the oil, ρ =SG denity of water

                                                           = 0.8 1000

                                                           = 800 kg/

Let acceleration due to gravity, g = 9.81 m/

Volume of block submerged in oil is

Volume of block above the oil surface is

The total volume of the block is V = +

Therefore for a partially submerged body, we know that

Buoyant force = total weight of the block

and

total weight of the block = Weight of the fluid displaced by the block

ρ\timesV\timesg = ρ\times\times g

600(+) = 800

600 + 600 = 800

600 = 800 - 600

600 = 200

=

Thus = 600

        = 200

        V = 600+200

            = 800

Therefore fraction of volume of the block submerged in oil is,

        =

        =

answer:

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