Determine the total energy e of water vapor with a mass of 2.50 kg, a specific internal energy μ= 2780 kj/kg, traveling at a velocity of 56.0 m/s at a height of 3.50 m. first draw a sketch of your system

Total energy E of water vapor is 6954005.8 J

Explanation:

given data:

mass = 2.50 kg

specific internal energy μ = 2780 kJ/kg = 2780 ×10³ J/kg

velocity of water vapor = 56 m/s

height h or z = 3.50 m

we know that total energy is given as

total energy E = mμ + mv²  + mgh

                        = m(μ +v² +gh)

                        = 2.5(2780 ×10³ + ×56²+9.81×3.50)

                    E = 6954005.8 J

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answer:

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explanation: